Please answer part (c) for problem # 3. Sign In xSection 3.1 e chegg Study! Guid
ID: 2895727 • Letter: P
Question
Please answer part (c) for problem # 3.
Sign In xSection 3.1 e chegg Study! Guided Si X x C www.webassign.net/web/Student/Assignment-Responses/last?dep.16449920 3. 2.5/3 points | Previous Answers My Notes Ask Your This is Section 3.1 Problem 6: The revenue of a car dealer from car sales is a function of the advertising expenditure. Hence R f(a), where both of a and R are in thousands of dollars. (a) f(10)-50 means that if the the car dealer spends 10 thousands of dollars on advertising, then its revenue is 50 thousands of dollars ' (b) f"(10-2 means that for every increase of $1,000$ from 10 thousands of dollars spending on advertising, the car dealer's revenue increases by about 2 thousands of dollars (c) f(10.8) is approximate thousands of dollars 4 2/2 polnts | Previous Answers My Notes Ask Your This Is Section 3.1 Problem 22: For y=f(x)-x-r', x= 1, dy= -04 f(x)Ax and 4x=0.02; and Round to three decimal places unless the exact answer has less decimal places. 5. 2/2 points | Previous Answers My Notes Ask Your This Is Section 3.1 Problem 12: For y=r(x)--4x+3, x=5, and ax=0.2 : and 7:11 PM Type here to search 10/4/20171Explanation / Answer
Since, given f(10)=50 means that if car dealer spends 10,000 dollars on advertising then its revenue is 50 thousand dollars.
also, f'(10)=2, means that for every increase of 1,000$ from 10 thousand of dollars spending on advertising,the car dealer's revenue increases by about 2.
Now, as for every increase of 1000$ from 10 thousands of dollars spending on advertising, the car dealer's revenue increases by about 2.
so, for increase of 0.8 thousand of dollars= 800$ from 10 thousands of dollars spending on advertising the car dealer's revenue increases by about (2/1000)*800 = 1.6.
so ,f(10.8) could be 50+1.6=51.6 means that if car dealer spends 10800 dollars on advertising, then its revenue is approximately 51.6 thousand of dollars.