In a clinical trial of a drug used to help subjects stop? smoking, 758 subjects
ID: 2907346 • Letter: I
Question
In a clinical trial of a drug used to help subjects stop? smoking, 758 subjects were treated with 1 mg doses of the drug. That group consisted of 42 subjects who experienced nausea. The probability of nausea for subjects not receiving the treatment was 0.0114.
Complete parts? (a) through? (c).
a. Assuming that the drug has no? effect, so that the probability of nausea was 0.0114, find the mean and standard deviation for the numbers of people in groups of 758 that can be expected to experience nausea.
The mean is _______people.
?(Round to one decimal place as? needed.)
The standard deviation is ________ people.
?(Round to one decimal place as? needed.)
b. Based on the result from part? (a), is it unusual to find that among
758 people, there are 42 who experience? nausea? Why or why? not?
A.It is not unusual because 42 is within the range of usual values.
B.It is not unusual because 42 is outside the range of usual values.
C. It is unusual because 42 is within the range of usual values.
D. It is unusual because 42 is outside the range of usual values.
c. Based on the preceding? results, does nausea appear to be an adverse reaction that should be of concern to those who use the? drug?
A.The drug does not appear to be the cause of any nausea.
B.The drug does appear to be the cause of some nausea. Since the nausea rate is quite high?(about
6?%), it appears to be an adverse reaction that occurs very often.
C.The drug does appear to be the cause of some nausea. Since the nausea rate is still quite low?(about
6?%), it appears to be an adverse reaction that does not occur very often.
Explanation / Answer
The mean is =np=758*0.0114=8.6
standard deviation is sqrt(np(1-p))=2.9
b)
D. It is unusual because 42 is outside the range of usual values.
c)
B.The drug does appear to be the cause of some nausea. Since the nausea rate is quite high?(about
6?%), it appears to be an adverse reaction that occurs very often.