Disregard the original answers in the picture The data show the number of viewer
ID: 2908283 • Letter: D
Question
Disregard the original answers in the picture
The data show the number of viewers for television stars with certain salaries. Find the regression equation, letting salary be the independent (x) variable. Find the best predicted number of viewers for a television star with a salary of $3 million. Is the result close to the actual number of viewers, 8.0 million? Use a significance level of 0.05. 15 8 4.9 4.3 millions of Viewers (millions 1.4 4.4 Click the icon to view the critical values of the Pearson correlation coefficient r. What is the regression equation? y= 6.001' + (-0.024) x (Round to three decimal places as needed.) What is the best predicted number of viewers for a television star with a salary of $6 million? The best predicted number of viewers for a television star with a salary of $6 milion is 55 million (Round to one decimal place as needed.) Is the result close to the actual number of viewers, 3.9 million? XA. The result is very close to the actual number of viewers of 3.9 million. B. The result is not very close to the actual number of viewers of 3.9 million. O C. The result is exactly the same as the actual number of viewers of 3.9 million. 0 D. The result does not make sense given the context of the data.Explanation / Answer
(a)
Sum of X = 38.4
Sum of Y = 147
Mean X = 4.8
Mean Y = 18.375
Sum of squares (SSX) = 47.48
Sum of products (SP) = -74.9
Regression Equation = ? = bX + a
b = SP/SSX = -74.9/47.48 = -1.57751
a = MY - bMX = 18.38 - (-1.58*4.8) = 25.94703
? = -1.578X + 25.947
(b)
salary(X)=$ 6 million
? = -1.578(6) + 25.947 = 16.479
(c) The result is not very close to actual number of viewers of 3.9 million (b)