Following are observed frequencies. The null hypothesis is Ho:P1-0.5,P2-0.20,P3-
ID: 2909814 • Letter: F
Question
Following are observed frequencies. The null hypothesis is Ho:P1-0.5,P2-0.20,P3-0.10, P4-0.20 Category1 2 3 4 Observed 71 3 32 36 Senat Test the hypothesis that the distribution of the observed frequencies is as given by the null hypothesis. Use the 0.005 level of significance and the P-value method with the TI-84 Plus calculator (a) State the null and alternate hypotheses (b) Find the P-value. Round the answer to at least four decimal places. (c) Determine whether to reject Ho (d) State a conclusion. Part: 0/4 Part 1 of 4 (a) State the null and alternate hypotheses. Ho:P1-0.5,P2- 1,The distribution of the observed frequencies (Choose one) O-P3-O-P4-0.20 from that of the expected frequendies.Explanation / Answer
a)
Ho: p1=0.5 ; p2=0.2 ; p3=0.10 ; p4=0.20
H1: the distribution of observed frequencies are different from that of the expectd frequencies.
b)
applying chi square goodness of fit test:
fr abvoe test statsitic 15.924 and (categories-1=3) degree of freedom p value =0.0012
c)
as p value is less than 0.005 level reject Ho
d)
we have sufficient evidence to conclude that distribution of observed frequencies are different from that of the expectd frequencies.
observed Expected Chi square category Probability(p) Oi Ei=total*p R2i=(Oi-Ei)2/Ei 1 0.500 71.000 85.000 2.306 2 0.200 31.000 34.000 0.265 3 0.100 32.000 17.000 13.235 4 0.200 36.000 34.000 0.118 total 1.000 170 170 15.924