Please, help with the test! 2) Given D=20 and the bearing of the vector is N43°W
ID: 2911552 • Letter: P
Question
Please, help with the test!
2) Given D=20 and the bearing of the vector is N43°W, find the components of the vector D.
Round your answers to the nearest hundredth.
D < , >
3) Given Q=9 and the bearing of the vector is N60°E, find the EXACT components of the vector Q.
Give EXACT answers (no decimals).
Q = < , >
4) Find the magnitude and bearing (in degrees, 090) of the vector <3,4>.
Give your answers to the nearest hundredth.
Magnitude
Bearing
5) Given q has magnitude 9 and bearing N67°W and g has magnitude 18 and bearing S67°E, find the vector q + g.
Give your answer accurate to two decimal places.
q + g < , >
6)Given u has magnitude 20 and direction 133° and a has magnitude 18 and direction 293°, find the vector u + a in terms of its magnitude and direction.
Give your answers rounded to two decimal places.
Magnitude of u + a
direction from a standard position of u + a °
7)Given u has magnitude 12 and bearing N29°W and q has magnitude 9 and bearing S11°E, find the vector u + q as a magnitude and bearing.
Give your answer accurate to two decimal places.
magnitude of u + q
bearing of u + q
8)A person leaves home and walks 2 miles west, then 5 miles southwest.
How far from home is she?
_____miles
In what direction must she walk to head directly home?
N _____degrees E
9)Evaluate the expression (2+2i)(22i) and write the result in the form a+bi.
The real number a equals ____
The real number b equals ____
10) Evaluate the expression (34i)(44i) and write the result in the form a+bi.
The real number a equals ____
The real number b equals ____
11)Evaluate the expression (3+3i)(4+4i) and write the result in the form a+bi.
The real number a equals ___
The real number b equals ___
12) Evaluate the expression 7567 and write the result in the form a+bi.
The real number a equals ___
The real number b equals ___
12)
2 321Explanation / Answer
1) the vector reprresent in the figure is
< -2 , -1 >
magnitude = sqrt ( -2^2 + -1^2 )
= sqrt ( 4 +1 )
magnitude = 2.24
finding bearing
tan theta = -1/-2
theta = 26.565 degrees
bearing = 180 + 26.565 = 206.57 degrees