This assignment is past the original due date of Fri 03/16/2018 11:30 pm. You ha
ID: 2912067 • Letter: T
Question
This assignment is past the original due date of Fri 03/16/2018 11:30 pm. You have used a Late Problems answered correctly after the original due date are subject to a 10% pena Due in 2 hours, 54 mloutes. Due Sun 03/18/2018 11:30 A rock is thrown upward from a bridge that is 79 feet above a road. The rock re was thrown, t 3.32 seconds after it was thrown. Define a quadratic function. J. that gives the height of the rock above the road (an feet) in terms of the mumber of seconds clapsed since the rock Preview Points available on this attempt: 0.9 of original 1 Unlimited attempts Post this question to forumCExplanation / Answer
maximum height is reached at 0.51 sec
contacts the road after 3.32 sec
so , we can write the equation as
y = a ( x - 0.51)^2 + k
plugging two points
79 = a ( 0 - 0.51)^2 + k
79 = .2601a + k
0 = 7.8961 a + k
solving the two equations for a and k
a = -10.346
k = 81.69
hence , the equation is
y = -10.346 ( x - 0.51)^2 + 81.69
y = -10.346 t^2 + 10.5529 t + 78.999