Porphyrin is a pigment in blood protoplasm and other bodyfluids that is significant in boy energy and storage. Let x be arandom variable that represents the number of milligrams ofporphyrin per deciliter of blood. In healthy adults, x is appxnormally distributed with mean = 38 and standard deviation = 12. What is the probaility that: a. x is less than 60? b. x is greater than 16? c. x is between 16 and 60? d. x is more than 60? (This may indicate an infection,anemia or another tpe of illness.) Porphyrin is a pigment in blood protoplasm and other bodyfluids that is significant in boy energy and storage. Let x be arandom variable that represents the number of milligrams ofporphyrin per deciliter of blood. In healthy adults, x is appxnormally distributed with mean = 38 and standard deviation = 12. What is the probaility that: a. x is less than 60? b. x is greater than 16? c. x is between 16 and 60? d. x is more than 60? (This may indicate an infection,anemia or another tpe of illness.)
Explanation / Answer
Use the following website to solve this problem (alternatively youcan look for statistical tables by calculating Z score) http://www.stat.tamu.edu/~west/applets/normaldemo.html 1a) P(X < 60) = P(Z < 1.83) = 0.9666 1b) P(X > 16) = P(Z > -1.83) = 0.9666 1c) P( 60 > X > 16 ) = P( 1.83 > Z> -1.83 ) = 1 -0.0334 x 2 = 0.9332 1d) P( X > 60) = P(Z > 1.83) = 0.0334 Hope this helps!