If two balanced dice are roled: a) what is the probability that the sum of the t
ID: 2913612 • Letter: I
Question
If two balanced dice are roled: a) what is the probability that the sum of the two numbersthat appear will be odd? b) what is the probability that the sum of the two numbersthat appear will be even? c) what is the probability that the difference between the twonumbers that appear will be less than 3? If two balanced dice are roled: a) what is the probability that the sum of the two numbersthat appear will be odd? b) what is the probability that the sum of the two numbersthat appear will be even? c) what is the probability that the difference between the twonumbers that appear will be less than 3?Explanation / Answer
a) There are 36 possible outcomes (2) -1, (3) -2 (4) -3 (5)-4 (6) -5 (7) -6 (8) - 5 (9) - 4 (10) -3 (11) -2 (12)-1 The sum of odd outcomes = 2 + 4 + 6+ 4 + 2 = 18. so the probability = 18 / 36 = 1/2. b) The probability is 1 - p(odd) = 1 - 1/2 = 1/2 c) (1,1), (1,2), (1,3) (2,1), (2,2), (2,3), (2,4) (3,1), (3,2), (3,3), (3,4), (3,5) (4,2), (4,3), (4,4), (4,5), (4,6) (5,3), (5,4), (5,5), (5,6) (6,4), (6,5), (6,6) 24/36 = 2 /3