Please explain me how to get these two problems, these are drivingme crazy. Than
ID: 2914099 • Letter: P
Question
Please explain me how to get these two problems, these are drivingme crazy. Thank you so much!1. The ages of the 760 people participating in a large workshop (tothe nearest year) are summarized as follows:
Age 18 19 20 21 22 23 24 25 32
Number of students 14 85 220 215 190 30 3 2 1
What is true about the median age of the 760people?
A .It could be any number between 19 and 20.
B. It must be 20.
C. It must be 21.
D. It must be 22.
E. It must be over 22.
2. The course grade of a class is summarized as follows:
Grade A B C D F
Number of students 16 22 22 12 1
What is the median grade of the class?
a. A
b. B
c. C
d. N/A
Explanation / Answer
1. Age 18 19 20 21 22 23 24 25 32 no. of students 14 85 220 215 190 30 3 2 1 760 ¬total frequency cumulative frequency 14 99 319 534 724 754 757 759 760 Age 18 19 20 21 22 23 24 25 32 no. of students 14 85 220 215 190 30 3 2 1 760 ¬total frequency cumulative frequency 14 99 319 534 724 754 757 759 760 n=760 (even)median age would be the mean of n/2 and [(n/2)+1] i.e the 380th and381th item = (21+21)/2= 21 (since from cumulative frequency we can see380th and 381st item falls in 21 age group of people) 2. grade A B C D F no. of students (frequency) 16 22 22 12 1 cumulative frequency 16 38 60 72 73 n=73 (odd) median here =(n+1)/2 = 74/2 = 37th item = B grade (from above table we can see incumulative frequency 37th frequency falls in B grade) Age 18 19 20 21 22 23 24 25 32 no. of students 14 85 220 215 190 30 3 2 1 760 ¬total frequency cumulative frequency 14 99 319 534 724 754 757 759 760