Mary is takinga k day crash course in statistics. Therecord shows that she was a
ID: 2914445 • Letter: M
Question
Mary is takinga k day crash course in statistics. Therecord shows that she was absnet on days numberd n1, adifaiosdf nr.If the instruction feels that B is the largest unbeliavlbeprobabiltiy, will he or she conclude that Mary was losing intrestmroe towrad the end of the course? Does this work alsok=5
m=3
n=2
Same approach as number 4.
x=1,3,5 xbar=3
y=2,4 ybar=3
xbar-ybar=0
Total = C (5 3) = 10
x bar ' y bar'
1 3 5 3 2 4 3 0
1 3 2 2 4 5 9/2 -2.5
1 3 4 8/3 2 5 7/2 -0.83
3 5 2 10/3 1 4 5/2 0.83
3 5 4 12/3 12 3/2 2.5
2 4 1 7/3 3 5 8/2 -1.67
2 4 3 9/3 1 5 3 0
2 4 5 11/3 1 3 2 1.67
5 1 2 8/3 3 4 7/2 -0.83
5 1 4 10/3 2 3 5/2 0.83
xbar'-ybar'> xbar-ybar (Six times)
6/10=0.6=p
Mary is takinga k day crash course in statistics. Therecord shows that she was absnet on days numberd n1, adifaiosdf nr.If the instruction feels that B is the largest unbeliavlbeprobabiltiy, will he or she conclude that Mary was losing intrestmroe towrad the end of the course? Does this work also
k=5
m=3
n=2
Same approach as number 4.
x=1,3,5 xbar=3
y=2,4 ybar=3
xbar-ybar=0
Total = C (5 3) = 10
x bar ' y bar'
1 3 5 3 2 4 3 0
1 3 2 2 4 5 9/2 -2.5
1 3 4 8/3 2 5 7/2 -0.83
3 5 2 10/3 1 4 5/2 0.83
3 5 4 12/3 12 3/2 2.5
2 4 1 7/3 3 5 8/2 -1.67
2 4 3 9/3 1 5 3 0
2 4 5 11/3 1 3 2 1.67
5 1 2 8/3 3 4 7/2 -0.83
5 1 4 10/3 2 3 5/2 0.83
xbar'-ybar'> xbar-ybar (Six times)
6/10=0.6=p