Math Question: Supposed a basketball player has a 40% chanceof making a 3-pointer. What is the probability that he will make 5out of 10 3-point shot using the formulaP=(nCr)(pr)(1-p)n-r I don't know how to find P, probability of success? Math Question: Supposed a basketball player has a 40% chanceof making a 3-pointer. What is the probability that he will make 5out of 10 3-point shot using the formulaP=(nCr)(pr)(1-p)n-r I don't know how to find P, probability of success? I don't know how to find P, probability of success?
Explanation / Answer
n =10 players tottlal r = 5 because you are the question asks you to choose 5 p =.40 (sucess that they will make the shot) (1-p)= (1-40%)= .60 (chance of not making the shot, if 40%will make the shot then 60% wont make the shot all probablitieshave to add up to one all the time) Now plug in the numbers P=(nCr)(pr)(1-p)n-r P=(nCr) (combinationformula) (pr) (1-p)n-r P=(10 C5) * (0.40)^5 * (.60)^5 252 0.01024 .07776 =.20 (rouded) chance that they will shoot a 3 pointer(mutiply everything) P=(nCr)(pr)(1-p)n-r P=(nCr) (combinationformula) (pr) (1-p)n-r P=(10 C5) * (0.40)^5 * (.60)^5 252 0.01024 .07776 =.20 (rouded) chance that they will shoot a 3 pointer(mutiply everything)