Please assist with this problem; I think I've solved itcorrectly, but just want to double check. Problem: A card is eslected from an ordinary deck of 52cards. What is the probability of getting a) a queen b) a diamond I solved it as: P(card queen)= 4/52 P(card diamond) = 13/52 4/52 + 13/52 = 17/52 - 1/52 = 16/52 or (.3076923077) Please assist with this problem; I think I've solved itcorrectly, but just want to double check. Problem: A card is eslected from an ordinary deck of 52cards. What is the probability of getting a) a queen b) a diamond I solved it as: P(card queen)= 4/52 P(card diamond) = 13/52 4/52 + 13/52 = 17/52 - 1/52 = 16/52 or (.3076923077)
Explanation / Answer
Your answers are correct: a) P(Queen) = 4/52 b) P(Diamond) = 13/52 You don't need any of that other stuff you wrote (unlessthere's a third question that I'm not seeing).