Please check to ensure I have the correct answer. Ifnot, please provide me with
ID: 2916032 • Letter: P
Question
Please check to ensure I have the correct answer. Ifnot, please provide me with the correct one. Thanks Q: Consider the binonial random variable x withn= 50 and p = 0.5. Suppose we want to use anormal approximation to find the probability of at least 30successes. A reasonable approximation would be obtained bycomputing: - P(29.5 < x < 30.5) - P(x < 30.5) - P(x > 29.5) - P(59.5 < x < 100.5) The answer I have selected is the 1st P(29.5 < x < 30.5) Reasoning: Being that the X-valuethat we are using in the Binom. Equat. is 30 in falls between 29.5& 30.5. Is my thinking correct or am I offhere?? Thank You Please check to ensure I have the correct answer. Ifnot, please provide me with the correct one. Thanks Q: Consider the binonial random variable x withn= 50 and p = 0.5. Suppose we want to use anormal approximation to find the probability of at least 30successes. A reasonable approximation would be obtained bycomputing: - P(29.5 < x < 30.5) - P(x < 30.5) - P(x > 29.5) - P(59.5 < x < 100.5) The answer I have selected is the 1st P(29.5 < x < 30.5) Reasoning: Being that the X-valuethat we are using in the Binom. Equat. is 30 in falls between 29.5& 30.5. Is my thinking correct or am I offhere?? Thank You Thank YouExplanation / Answer
At least 30 successes means we have no less than 29successes. In other words, we are looking for the probabilityof having 30, 31, ... or 50 successes. Using the continuitycorrection, we give half of the difference between 29 and 30 to the30th success. Thus, we are trying to find P(X > 29.5).