Consider three elements {e1; e2; e3} put intorandom order as in the table below.
ID: 2917308 • Letter: C
Question
Consider three elements {e1; e2; e3} put intorandom order as in the table below.list ¦e1e2e3 ¦e1e3e2 ¦e2e1e3 ¦e2e3e1¦e3e1e2¦ e3e2e1
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probability ¦ 1/2 ¦ 1/4 ¦ 1/8 ¦ 1/16 ¦ 1/32¦ 1/32
Calculate the following quantities:
(a) P(e3 precedes e2); (b) P(e2 is in position 2); (c) E( positionof e1)
Consider three elements {e1; e2; e3} put intorandom order as in the table below.
list ¦e1e2e3 ¦e1e3e2 ¦e2e1e3 ¦e2e3e1¦e3e1e2¦ e3e2e1
________________________________________________________
probability ¦ 1/2 ¦ 1/4 ¦ 1/8 ¦ 1/16 ¦ 1/32¦ 1/32
Calculate the following quantities:
(a) P(e3 precedes e2); (b) P(e2 is in position 2); (c) E( positionof e1)
Consider three elements {e1; e2; e3} put intorandom order as in the table below.
list ¦e1e2e3 ¦e1e3e2 ¦e2e1e3 ¦e2e3e1¦e3e1e2¦ e3e2e1
________________________________________________________
probability ¦ 1/2 ¦ 1/4 ¦ 1/8 ¦ 1/16 ¦ 1/32¦ 1/32
Calculate the following quantities:
(a) P(e3 precedes e2); (b) P(e2 is in position 2); (c) E( positionof e1)
Explanation / Answer
for a and b all you have to do to find the probability that happensis add the probabilities that satisfy the condition a. 1/4 + 1/32 + 1/32 = 10/32 or 5/16 b. 1/2 + 1/32 = 17/32