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Question
A9PVVISszJIUo5kCL.9pTenN5 beukuSo... x/st.exe/1o Secure https//www-awh.aleks.com/aleksogi ACOTIONAL TOPICS NTR?OONOMETRY Asher Rinding magnitudes of forces related to an object suspended An object is placed on a cable hanging between two poles, as shown in the figure below. The object weighs 60 N. Find the tension in the cable to the left of the object and the tension in the cable to the right of the object. Carry your intermediate computations to at le ast 4 decimal places. Round your final answers to the nearest tenth. Tension in left part of cable: N Tension in right part of cable: UN 60 N Check O Type here to searchExplanation / Answer
let the tension in cable to the left of the object be x , to the right of the object be y
equilibrium equations are
x cos22o=y cos25o, x sin22o +y sin25o =60
=>y =x cos22o/cos25o, x sin22o +y sin25o =60
=> x sin22o +(x cos22o/cos25o)sin25o =60
=> x sin22o + x cos22otan25o =60
=> x (sin22o + cos22otan25o) =60
=> x =60/(sin22o + cos22otan25o)
=>x=74.353171525362539523448463182494
y =x cos22o/cos25o, x=60/(sin22o + cos22otan25o)
=>y =(60/(sin22o + cos22otan25o) )cos22o/cos25o
=>y =76.065836750184878255104503113816
Tension in left part of cable is 74.4 N
Tension in right part of cable is 76.1 N
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