Math 3301, IC 1-07 Exercise 1. A hotel chain divides its room offerings into two
ID: 2922039 • Letter: M
Question
Math 3301, IC 1-07 Exercise 1. A hotel chain divides its room offerings into two classes: Basic rooms and Suites, where suites have more space and features. It has four hotels in a city, idenitified as at (A) Airport, (D) Downtown, (R) Riverside and (H) Highway. Over a week, the occupancy numbers are recorded. The results are in the following table. A D R H Basic 56 60 47 122 Suite 22 45 38 48 (A) What is the size of this sample? (B) How many rooms were rented at the Riverside hotel? (C) What proportion (that is, relative frequency) of the stays were at theAirport hotel? Give your answer to the nearest tenth of a percent. Give your answer to the nearest tenth of a percent. basicrooms at the Highway hotel? Give your answer to the nearest tenth of (D) What proportion (that is, relative frequency) of the stays were inSuites? (E) What proportion (that is, relative frequency) of the stays were in a percent. Exercise 2. Letxx155 be a list of numbers, arranged in Suppose x77-33.5, x78-34.4, x79-35.4 and x80 = 36.4 order. (A) What is the median of this list? (B) What is 80 Ci i=77 (C) What is 80 (xi -77 +1)?Explanation / Answer
Solution:-
A) The size of this sample is 438.
Total sample size = 56 + 22 + 60 + 45 + 47 + 38 + 122 + 48 = 438
B) The number of rooms that are rented at riverside hotel = 47 + 38 = 85
C) The proportion of the stays were at airport hotel is 0.1781 or 17.8%.
The number of rooms that are rented at airport hotel = 56 + 22 = 78
Total number of rooms = 438
The proportion of the stays were at airport hotel = 78/438 = 0.1781
D) The proportion of the stays were insuits hotel is 0.3493 or 34.9%.
The number of rooms that are rented at insuits hotel = 153
Total number of rooms = 438
The proportion of the stays were insuits hotel = 153/438 = 0.3493.
E) The proportion of the stays were inbasic rooms at highway hotel is 0.7176 or 71.8%.
The number of rooms that are basic rooms and at highway = 122
Total rooms at highway hotels = 122 + 48 = 170
The proportion of the stays were insuits hotel = 122/170 = 0.7176.