I need to know how to determine the missing probability of amissing item. I have the following info. X= 1 2 3 4 5 p(x)= .16 .22 ? .20 .14 What is the answer to the question mark and how do I findit? I need to know how to determine the missing probability of amissing item. I have the following info. X= 1 2 3 4 5 p(x)= .16 .22 ? .20 .14 What is the answer to the question mark and how do I findit?
Explanation / Answer
We know that sum of probability in a probabilityfunction is one. Let us call the probability of random variable takes the value3 is a. As above i mentiond sum of the probability is one So apply that w get the value of a. ==> 0.16+0.22+a+0.20+0.14=1 ==>a=1-0.72=0.28 X= 1 2 3 4 5 p(x)= .16 .22 0.28 .20 .14 ==> 0.16+0.22+a+0.20+0.14=1 ==>a=1-0.72=0.28 X= 1 2 3 4 5 p(x)= .16 .22 0.28 .20 .14 X= 1 2 3 4 5 p(x)= .16 .22 0.28 .20 .14