Hey can some one help me with this one please I am reallystruggling with this on
ID: 2951396 • Letter: H
Question
Hey can some one help me with this one please I am reallystruggling with this one
There is a standard deck of 52 cards with which you will play agame of blackjack with the card dealer. (Of course, the deckhas been shuffled.) You will get a black jack if the value of yourcards sums to 21, with an “Ace” having a value of 11and the so-called face cards having a value of 10. (Those ofyou who know how to play black jack know that an “Ace”can also have a value of 1. To make this simpler, let’sjust let an “Ace” equal 11.) Two cards are dealtto you and two cards to the dealer. You are trying to win thegame.
a) The dealer offer you two ways he could deal the cards toyou.
· Method1: He deals you a card, then he takes a card; he deals you asecond card and then deals himself a second card.
· Method2: He deals you two cards then he deals himself two cards.
·
Under which method are you more likely to get a “blackjack” with just the first two cards dealt you?
b) What is the probability the first card will be an ace?
c) Given the first card was anace, what is the probability the second card is a 10, Jack, Queenor King?
d) What is the probability of getting a blackjack when the dealerdeals you the two cards first?
Explanation / Answer
b) probability fist card an ace=4/52 c)given first card ace what is probability second card is facecard=16/51 d) what probability of getting black jack with first two cards=2(2/52)16/51 The two is getting card ace or face card , or face card or ace a)deal card so I get first and third card again probability of ace = 4/52 probability third card is face card is less than or equal to 40/50(less than if secon cardis face card) probability of black jack on first or third card is less than orequal to 2(4/52)40/50 comparing d anf this answer d is larger