The number of red blood cells per square unit visible under amicroscope follows a Poisson distribution with average number 4.Find the probability of less than 2 blood cells are visiblefrom a half square units. I am not really sure what my should be here. Iknow how to solve it if I could just figure out the . Iam pretty sure that I can not presume that there is 2 red bloodcells per 1/2 square unit because the average does not dictatehow those red blood cells are distributed. Any help would beappreciated! Thanks! The number of red blood cells per square unit visible under amicroscope follows a Poisson distribution with average number 4.Find the probability of less than 2 blood cells are visiblefrom a half square units. I am not really sure what my should be here. Iknow how to solve it if I could just figure out the . Iam pretty sure that I can not presume that there is 2 red bloodcells per 1/2 square unit because the average does not dictatehow those red blood cells are distributed. Any help would beappreciated! Thanks!
Explanation / Answer
The number of red blood cells per square unit visible under a microscope follows a Poisson distribution with average number 4. Find the probability of Poisson Distribution: i p=e^(-?)*?^(x)/x! a) more than 5 blood cells are visible from a square unit. ii p(x>5)=1-e^(-4)*4^(5)/5! = ?=4, x>5 iii 0.214869613 b) exactly 4 blood cells are visible from two square units. Poisson Distribution: ?=4, x=4 i p=e^(-?)*?^(x)/x! ii p(x=4)=e^(-4)*4^(4)/4! = iii 0.1953668148 iv 2*0.1953668148 = v 0.3907336296 c) less than 2 blood cells are visible from a half square units. Poisson Distribution: ?=4, x