Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Part (a): The following table gives the probability distribution of therandom va

ID: 2953036 • Letter: P

Question

Part (a):

The following table gives the probability distribution of therandom variable X, the number of foreign tours a minister make in ayear.

X            1             2            3            4             5

P(X)       0.1          0.2         0.3         0.3          0.1

Find the probability that:

i) Minister makes visit between 2 and 5 (both exclusive)

ii) Minister makes at the most 4 tours

Part (b):

The range of the random variable X is [0, 1, 2, 3, x], where xis unknown. If each value is equally likely and the mean of X is 6,determine x.

Part (c):

Show that the following function satisfies the properties of ajoint probability mass function.

X        Y        f(x,y)

-1        -2         1/8

-0.5     -1         1/4

0.5      1         1/2

1         2         1/8

Also determine E(X) and E(Y)

Question2                                                                                                  3+12=15Marks

Part (a):

Discuss what is meant by the concept of independence of twodiscrete random variables.

Part (b):

Given is the joint probability distribution of X and Y.

       Y

X            0          1          2          3          g(X)

0             0.05     0.05     0.10     0          0.20

1             0.05     0.10     0.25     0.10      0.50

2             0          0.15     0.10     0.05      0.30

h(Y)        0.10     0.30     0.45     0.15      1.00

Determine the followings.

       I.      Mean of X and Mean of Y

     II.      Var(X) and Var (Y)

   III.      Cov (X, Y)

IV.      Correlation coefficientr.

Explanation / Answer

Part (a):

The following table gives the probability distribution of therandom variable X, the number of foreign tours a minister make in ayear.

X            1             2            3            4             5

P(X)       0.1          0.2         0.3         0.3          0.1

Find the probability that:

i) Minister makes visit between 2 and 5 (both exclusive)

   Add up the probabilities of the Minister making 2,3, 4, or 5 visits

    0.2 + 0.3 + 0.3 + 0.1 = 0.9


ii) Minister makes at the most 4 tours

   Add up the probabilities the Minister makes 1, 2,3, or 4 visits

   0.1 + 0.2 + 0.3 + 0.3 = 0.9