I am having the HARDEST time with this probability word problem.Can someone out

Question

I am having the HARDEST time with this probability word problem.Can someone out there please help?
A bag contains 7 cherries, 5oranges, and 3 lemon candies. Youreach in and take 3 pieces of candy at random. Find the probabilitythat you select at LEAST 1 cherrycandy.
The answer is: .877
but can someone tell me how they got that answer? whichformula did you use?
I'd very much appreciate it,
thank you!

A bag contains 7 cherries, 5oranges, and 3 lemon candies. Youreach in and take 3 pieces of candy at random. Find the probabilitythat you select at LEAST 1 cherrycandy.
The answer is: .877
but can someone tell me how they got that answer? whichformula did you use?
I'd very much appreciate it,
thank you!

Explanation / Answer

When you see the phase, at least 1, think about approachingthe problem by complement. Find the probability of not getting any cherries. P(no cherries) = 8/15 * 7/14 * 6/13 P(at least 1 cherry) = 1 - P(no cherries) = 1 - 8/15 * 7/14 * 6/13 Hope this helps, Mike

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