The number o leasable square feet of office space available in a city on any giv

Question

The number o leasable square feet of office space available in a city on any given day has a normal distribution with mean 640,000 square feet and a standard deviation of 18000 square feet. what is the interquartile range for this distribution.

Any ideas how to do this one. I tried adding one standard deviation and subtractiong one standard deviation from the mean and then subtracting these values from each other, but that was not the answer.

also can anyone explain why the answer to this problem is not all of the above?:
Sampling error occurs
a. when interviewers make mistakes resulting in bias
b. because a sample statistics is used to estimate a population parameter (answer)
c. when interviewers use judgment instead of random choice in picking the sample
d. when samples are too small

any help would be great

Explanation / Answer

Let X be the number of leasable square feet. Then, suppose X is N(m, s^2). Here m =640,000 and s = 18,000 If we standardise X, then Z = (X - m)/s is N(0,1). Now let's find the interquartile range for Z. We obtain this from tables of the standard normal distribution. P(Z

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