A) the body temperature of adults are normally distributed with a mean of 98.6F

Question

A) the body temperature of adults are normally distributed with a mean of 98.6F and a SD of 0.60F. if 25 adults are randomly selected find the probability that their mean body temperature is less than 99F.

B) Find the area under the standard normal curve between z=1 and z=2

C) Assume that the heights of women are normally distributed with a mean of 63.6 inches and a SD of 2.5inches. If 100 women are randomly selected find the probability that they have a mean height greater than 63.0 inches.

Explanation / Answer

(a) Given X~Normal(mean=98.6, s=0.6) n=25 The probability is P(xbar < 99) = P((xbar-mean)/(s/sqrt(n)) < (99-98.6)/(0.6/5)) =P(Z< 3.33) = 0.9995 (check standard normal table) ------------------------------------------------------------------------------ (b) P(1 (63-63.6)/(2.5/10)) =P(Z>-2.4) = 0.9918 (check standard normal table)

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