Please Answer To solve the separable differential equation 8 yy\' = x we must fi

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To solve the separable differential equation 8 yy' = x we must find two separate integrals (keep the constant 8 with the ij terms and use C for the constant of integration): integral dy = and integral dx = Solving for y we get two solutions, one positive y = and one negative y = (NOTE: On the above answer you must simplify all arbitrary constants down to one constant k. For example reduce an expression like (x2 + C)/5 to (x2/5 + k). Find the particular solution satisfying the initial condition y(0) = 9. y(x) =

Explanation / Answer

first blank: 8y

second: 4y^2

third: x

fourth: (1/2)x^2

fifth: sqrt(x^2/8+k)

sixth: -sqrt(x^2/8+k)

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