Please give descriptive solution!! In the figure shown below, gear 2 is input an
ID: 2996126 • Letter: P
Question
Please give descriptive solution!!
In the figure shown below, gear 2 is input and gear 5 is out. The gears form a regular gear train ( the arm is fixed and pins are fixed in place). Determine the gear ratio, the output gear rpm, and the output gear direction of rotation. Gear 2 is input running at 100 rpm CCW. Gear 5 is a ring gear and is the output. Note that the drawing is not to scale. All the gears have the same diametral pitch. The number of teeth are as follows (you can findN5): In the figure shown above, gear 2 is input and gear 5 is fixed. The arm is the output. The gears form a planetary gear train (the arm is free to rotate). Determine the gear ratio, the output arm rpm, and the output arm direction of rotation. Gear 2 is input running at 100 rpm CCW. Gear 5 is a ring (internal) gear. Note that the drawing is not to scale. All the gears have the same diametral pitch. Also determine the rpm of gear 4.Explanation / Answer
Gear ratio = (No. of teeths in O/P)/(No. of teeths in I/P)
a) Gear ratio b/w gear 2 and 3 = N3/N2
b) Gear ratio b/w gear 3 and 4 = N4/N3
c) Gear ratio b/w gear 4 and 5 = N5/N4
Final gear ratio = a x b x c = N5/N2
N5= 2 x N4 + 2x N3 + N2 = 120
That is to say, the number of teeth in the ring gear is equal to the number of teeth in the middle sun gear plus twice the number of teeth in the planet gears.
Final gear ratio = 120/20 = 60
Also, rpm of gear 2 is known (100 rpm) . Rpm of gear 3 = (N2/N3) x 100 = 100 rpm
Rpm of gear 4 = (N3/N4) x 100 = (2/3) x 100 = 66.67 rpm
Rpm of gear 5 = (N4/N5) x 66.67 = 16.7 rpm
Direction of rotation: Gear 5 will rotate in same direction as gear 2.
2) If gear 5 is fixed, and the arm is th O/P
Rpm of the arm = Rpm of the gear 5 calculated above = 16.7rpm
Direcction: Opposite to the direction of rotation of gear 2