Mixture of 6 pounds of fertilizer A, 16 pounds of fertilizer B, and 5 pounds of

Question

Mixture of 6 pounds of fertilizer A, 16 pounds of fertilizer B, and 5 pounds of fertilizer c prove optimal nutrients for a plant. Brand X contains equal parts of fertilizer B and fertilizer C, Brand Y part of fertilizer A and two of fertilizer B. Brand Z contains two parts two of fertilizer A, five parts of B, and two parts of fertilizer C, How mu ch of each brand is needed to obtain the Given systems of equations is _ (Linear/Nonlinear) Given systems of equations is _ (Linear/Nonlinear) xy - x^2 = -20 x - 2y = 3 1/x + 1/y = 7/5 1/x - 3/y = 4/5

Explanation / Answer

xy-x2=-20

x-2y=3

x=3+2y

Substituting back the value of x we get

(3+2y)y-(3+2y)2=-20

3y+2y2-9-4y2-12y+20=0

y=-11/2,1

when y=-11/2,x=-8

and when y=1,x=5

Hence the solution set is (-8,-11/2),(5,1)

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