For the 2^nd degree equation in two variables y^2 - 16x + 2y + 1 = 0 answer the
ID: 3014836 • Letter: F
Question
For the 2^nd degree equation in two variables y^2 - 16x + 2y + 1 = 0 answer the following: a. Type of conic ___________ b. Equation in standard form _______________ (must) c. h __________ d. k __________ e. p ____________ (be sure the sign is correct) f. Orientation __________ (horiz/vert and right, left, up or down) g. Vertices ____________ h, Foci _____________ i. Axes of symmetry ________________ (this must be the equation of a line) j. Length of latus rectum _____________ k. Endpoints of latus rectum __________________ 1. Directrix _____________ (this must be the equation of a line) m. Sketch (accurately) on graph paper, showing all of the above details. q. List the necessary entries you would use on the Y = screen of your graphics calculator to view this conic in its entirety (not all Y, need be used) Y_1 = ___________ Y_2 = ____________ Y_3 = ____________Explanation / Answer
y^2 -16x + 2y +1 = 0
Conics : Parabola
(y +1)^2 -1 = 16x -1
Standrad form : 4p(x-h) = (y - k)^2
16x = ( y +1)^2 : Standard form
h = 0 ; k = -1 ; p = 4
Orientation : left
Vertices ( 0,-1)
foci = ( 4, -1)
Axis : y = -1
Directrix : x = -4