I need the answer for A , B and C metandymu are tutoring emeral high statements

Question

I need the answer for A , B and C

metandymu are tutoring emeral high statements below, you need to tell them whether their school students. When the students make the students how to think about the statements are true or not and to explain why they are true or not true. You need to explain to the Because that's how it works. oe because that's thenule are not sufficien (a) The first student says 22 x 2 -2 since 2 3 5. The second student says: 2 x 21 43 sinoe 2 3 5 and 2 x 2 4. The first student says (2 27 since3+4-7. The second student says (23) 212 since 3 x 4 12. (c) The first student says: 3 2 3-2 since 1/2 -2. The second student says: 3 because that's how it works The third student says: 3 v3because that's how it works.

Explanation / Answer

Dear Student Thank you for using Chegg !! a) Student 1: 2^2 X 2^3 = 2^5 Student 2: 2^2 X 2^3 = 4^5 Solution Solution given by student 1 is correct because as per property of exponents in case of multiplication of two exponential terms with common base The exponents of two terms are added while retaining the base as it is i.e. x^m X x^n = x ^ (m + n) Sicne student 2 has modified the base also therefre student 2 solution is false and incorrect. b) Student 1: (2^3)^4 = 2^7 Student 2: (2^3)^4 = 2^12 Student 3: (2^3)^4 = 2^81 Solution Solution given by student 2 is correct because as per property of exponents in case of multiplication of two exponential i.e. (x^m)^n = x ^ (m * n) c) Student 1: 3^1/2 = 3^-2 Student 2: 3^1/2 = 1/3^2 Student 3: 3^1/2=sqrt(3) Solution Solution given by student 3 is absolutely correct. Student 1 solution is incorrct because two real numbers such as 1/2 and -2 can never be equal Student 2 is also incorrect for the similar reason as stated for student 1. Two real numbers can never be equal. Student 3 is correct because if we square the two sides of equation then LHS = 3^1/2 RHS => on squaring sqrt(3) (3^1/2)^2 On squaring 3 3 Hence Proved

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