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Consider the set X to be a collection of colored shaped objects, where X = {red

ID: 3037175 • Letter: C

Question

Consider the set X to be a collection of colored shaped objects, where X = {red triangle, blue square, yellow circle, red circle, yellow triangle, green circle}. For a, b elementof X, let's say a ~ b if object a is the same shape as object b. (a) Prove that ~ is an equivalence relation. (For example, "a ~ a because a has the same shape as itself") (b) List the equivalence classes of ~ on X. Describe them, i.e. for each class, say what's in common among all of its elements. (c) Why is[triangle]not an equivalence class on this set X?

Explanation / Answer

For notational convenience , let R be the given relation.

By definition, aRb if a has the same shape as b.

(a) Claim : R is an equivalence relation

(1) R is reflexive: aRa for a, as a and a have the same shape

(2) R is symmetric: aRb implies a has the same shape as b , which means b has the same shape as a

which in trun means bRa.

(3) R is transitive: If aRb and bRa, then clearly a and have the same shape, so aRc is true.

Hence R is an equivalence relation.

(b) List all equialence classes.

C = { a: a is a circle}

T = {a: a is a triangle}

S = {a: a square}

(c) [triangle ] is indeed an equivalence class , as noted above.