Classify drivers in terms of accident risk: You define the top 25% of drivers to
ID: 3041725 • Letter: C
Question
Classify drivers in terms of accident risk:
You define the top 25% of drivers to be Good, the bottom 25% to be Bad and the rest as Medium. From historical data you believe that Good drivers have a 95% chance of no accident in any given year, Medium drivers have a 90% chance, and Bad drivers have a 75% chance. You also believe that the chance of having multiple accidents in a given year is 3% for Good drivers, 5% for Medium drivers, and 15% for Bad drivers.
What is the probability that a driver has EXACTLY ONE ACCIDENT in a year for each:
i.Good Driver
ii.Medium Driver
iii.Bad Driver
Explanation / Answer
For any driver,
P( 1 accident | driver is of class X) =P( less than or equal to 1 accident | class X driver)-P(0 accident | class X driver)=(1-P( more than 1 accident | class X driver)) - P(0 accident | class X driver)
= (1 - P( multiple accidents | class X driver)) - P(no accidents | class X driver)
so, P( 1 accident and driver is good) = P(1 accident | Good driver)*P(Good driver) = (1 - 0.03 - 0.95)*0.25 =0.02*0.25= 0.005
P( 1 accident and driver is medium) = P( 1 accident | medium driver )*P(medium driver)
= (1 - 0.05-0.9)*0.5=0.05*0.5=0.025
P( 1 accident and driver is bad ) =P(1 accident | driver is bad)*P(driver is bad)=(1-0.15-.75)*.25=0.10*.25=0.025
So,
P( 1 accident | Good)=0.02 P( 1 accident and good) = 0.005
P( 1 accident | medium) = 0.05 P( 1 accident and medium ) = 0.025
P( 1 accident | bad ) = 0.10 P( 1 accident and bad ) = 0.025