Assume that, on the average, normal rhesus monkeys spend an mean of 60 minutes d
ID: 3042656 • Letter: A
Question
Assume that, on the average, normal rhesus monkeys spend an mean of 60 minutes dreaming while sleeping at night (thus, µ = 60 minutes). Time spent dreaming is typically referred to as REM sleep (Rapid Eye Movement). You are interested in the effects a new dream-enhancing drug has on dreaming since an increase in the time spent dreaming while sleeping is thought to be a good thing in terms of getting a “restful” sleep. You want to pursue testing the drug in humans if there is any evidence that it significantly increases nightly dreaming time in these nonhuman primates. Ten rhesus monkeys are administered the drug in the morning and their dream time (in minutes) is monitored that night. The alternate hypothesis is: the drug will increase time spent dreaming, or the time in REM sleep. You obtain the following times (minutes) each monkey spent dreaming:
52, 69, 74, 60, 67, 65, 69, 55, 63, 68
Complete step 3 of the hypothesis testing procedure and calculate z or t, whichever is appropriate for these data. Round to the nearest hundredths place. If your calculated z or t is not identical to one of the values below, but within plus or minus 0.2 of an answer below, assume it's a rounding error and select the answer that is closest to your calculated value. Ignore the minus sign if your calculated z or t is negative.
a.1.68 b.1.95 c.2.18 d. 2.34 e. 2.52 f. 2.61 g. the correct value of z or t is not listed in alternatives "a" through "f", even when taking into consideration a rounding error of plus or minus 0.16.
Explanation / Answer
There are n=10, so a t-test is appropriate here.
Degrees of Freedom=10-1=9
This is a one-sided t-test .
Mean = 64.2
Standard deviation = 6.462
T-stastic=(64.2-60)/[6.462/sqrt(9)]=1.95