I know what the answers are to b,c,d but not sure how to find them. Please show

Question

I know what the answers are to b,c,d but not sure how to find them. Please show work. what policy implications do they suge networks? 2.99 Estimate the standard deviation for the underlying distribution of measurements from each of the following data summaries. (Assume that the data in each case are obtained from a bell-shaped distribution.) L b. The personnel officer for a major manufacturing organization reports that for the past year the daily absenteeism rate in her company has ranged from 3 to 27. 7.20% c Over a two-week period (10 market days) the daily change in the Dow-Jones industrial average ranged from -14 3/4 on Tuesday of the first week to +6 7/8 on Thursday of the second week 25,61.d. The annual advertising and promotional budgets of 20 residential real estate firms that operate in the San Francisco area were recorded. The least expenditure on advertising and promotion among this group was $29,450; the greatest, $133,000. i Iveted in the center of a very rich valley known for its production of

Explanation / Answer

b)

According to range rule the standard deviation is approximately equal to one fourth of the range of the data so

Standard Deviation = Range / 4

Here we have maximum value 27 and minimum value 3.

So we can find the range using the following formula

Range = Maximum value – Minimum Value

Range = 27 – 3

= 24

Thus,

Standard Deviation = 24 / 4

                                = 6

c)

Here we have,

Minimum Value = -14 (3/4) = -14.75 and

Maximum Value = 6 (7/8) = 6.875

Thus, the standard deviation is

Standard Deviation = Range / 4

Range = Maximum Value – Minimum Value

Range = 6.875- (-14.75)

Range = 21.625

Then

Standard Deviation = 21.625 / 4

                                = 5.40625

d)

Here we have,

Minimum Value = 29450 and

Maximum Value = 133000

Thus, the standard deviation is

Standard Deviation = Range / 4

Range = Maximum Value – Minimum Value

Range = 133000 - 29450

Range = 103550

Then

Standard Deviation = 103550 / 4

                                = 25887.5

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