Microsoft Word-Part 2 -Ans x G biomedical reductionism G chs.ethinkeducation.com
ID: 3047083 • Letter: M
Question
Microsoft Word-Part 2 -Ans x G biomedical reductionism G chs.ethinkeducation.com/p ES Baptist College of." MyCampus . BCHS Ernail Netflix m Moodle R 1Hl: Learning Mana Home | Chegg.com 2. Question 2a - 2d are based on a distribution of scores with X(mean)-75 and standard deviation 6.38. Draw a picture to illustrate the distribution over 3 standard deviations. What is the probability (area under the curve) of a score falling between a raw score of 70 and 80? What is the probability of a score falling above a raw score of 80? What is the probability of a score falling between a raw score of 81 and 83 What is the probability of a score falling below 63. a. b. c. d.Explanation / Answer
Solution:-
5)
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: = 16
Alternative hypothesis: 16
Note that these hypotheses constitute a two-tailed test. The null hypothesis will be rejected if the sample mean is too big or if it is too small.
Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method is a one-sample z-test.
Analyze sample data. Using sample data, we compute the standard error (SE), z statistic test statistic (z).
SE = s / sqrt(n)
S.E = 0.675
z = (x - ) / SE
z = - 1.48
where s is the standard deviation of the sample, x is the sample mean, is the hypothesized population mean, and n is the sample size.
Since we have a two-tailed test, the P-value is the probability that the z statistic less than -1.48 or greater than 1.48.
Thus, the P-value = 0.1389
Interpret results. Since the P-value (0.1389) is greater than the significance level (0.05), we cannot reject the null hypothesis.
From the above we can conclude that the kids in Remulak as sick as teh kids throughout the state.