Problem 1: The distribution of ages of students in a class is given below. Compl
ID: 3047224 • Letter: P
Question
Problem 1: The distribution of ages of students in a class is given below. Complete the table and use the results to calculate 2 and (the mean, variance and standard deviation of X), (Don't forget to include the calculations for x 20 when you sum the columns!) xffx) 202(0.05)-400(0.05) 20.0 20 | 0.05 | 21 0.10 22 0.30 23 0.40 20(0.05-1.0 24 0.15 Total 2(xf(x) ) = (When finding the totals, don't forget the 1.0 and 20.0 from the first row of the table!)*** mean = 2( xf(x) ) variance-02 = ( x2f(x) )-u2- standard deviation = =Explanation / Answer
The table is
Mean = 22.50
Variance = x2P(X) - 2 = 507.3 - 22.502 = 1.05
Standard deviation = sqrt (variance) = sqrt(1.05) = 1.0247
x f(x) xf(x) x^2f(x) 20 0.05 1 20 21 0.1 2.1 44.1 22 0.3 6.6 145.2 23 0.4 9.2 211.6 24 0.15 3.6 86.4 Total 1 22.5 507.3