Refer to the following for parts c) and d): The following data are sample means
ID: 3048314 • Letter: R
Question
Refer to the following for parts c) and d): The following data are sample means of (wing length -- tail length) in millimeters (mm) for 24 flycatchers in each of 10 different species of the flycatcher. (Note: a flycatcher is a type of bird.)
| Species | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
|---------|---|---|---|---|---|---|---|---|---|----|
| Avg (Wing - Tail) | 13.6 | 15.4 | 14.7 | 12.4 | 9.2 | 13.7 | 10.3 | 7.0 | 9.5 | 9.5 |
Explain why a conclusion that this measurement tends to differ in the 10 species cannot be made from these averages alone. What is the additional piece of information needed to test for group differences and to evaluate the extent to which individuals from different species can be distinguished?
What is the grand mean for this collection of observations?
Explanation / Answer
Refer to the following for parts c) and d): The following data are sample means of (wing length -- tail length) in millimeters (mm) for 24 flycatchers in each of 10 different species of the flycatcher.
Here we have given that,
sample size (n) = 24
And there are 10 different species.
Here we have to test ten population means. Since we use one way ANOVA for this data.
Explain why a conclusion that this measurement tends to differ in the 10 species cannotbe made from these averages alone.
For testing ten means we need sample means and standard deviations.
Then only we can test ten means.
What is the additional piece of information needed to test for group differences and to evaluate the extent to which individuals from different species can be distinguished?
So we need additional information is standard deviation.
What is the grand mean for this collection of observations?
The grand mean is the average of these 10 different species.
Therefore grand mean = (13.6+15.4+14.7+12.4+9.2+13.7+10.3+7.0+9.5+9.5) / 10
Grand mean = 11.53