Import the Getting To Know You Survey data, the following code might help. NoU =
ID: 3048800 • Letter: I
Question
Import the Getting To Know You Survey data, the following code might help.
NoU = read.csv("http://users.stat.umn.edu/~kinne174/Getting2NoUS18.csv", header=T) attach(NoU)
R problem 1:
SHOW ME ALL STEPS FOR THE R CODE THANK YOU!
(a) We are interested in the proportion of students at the U are originally from Minnesota. Let p be the true proportion of students at the U that are originally from Minnesota. Calculate and interpret pˆ based on the survey data.
Hint: you can use the command below to find the count of people from Minnestoa:
table(from.MN)
(b) Suppose it is known that the U admits 60% from Minnesota every year.
(i) Calculate the mean and standard deviation of the sample proportion of students who are from Minnesota.
(ii) What is the shape of sampling proportion distribution?
Explanation / Answer
Solutiona:
dim to know obsetvarions and columns
view to view dataframe
NoU = read.csv("http://users.stat.umn.edu/~kinne174/Getting2NoUS18.csv", header=T)
View(NoU)
head(NoU,5)
dim(NoU)
477 33
there were 33 columns and 477 observations
table(NoU$from.MN)
No Yes
187 290
there were 290 students from MN
using prop.table we get the proportion of students from MN
prop.table(table(NoU$from.MN))
Output:
No Yes
0.3920335 0.6079665
p^=sample proportion of students at the U that are originally from Minnesota.
=0.6079665
Solutionbi:
290 are from Minnesota
290+187=477=total
mean of sample propotion of students who are from =p^=successess/total
=187/477=0.6079665
which we calculated earlier using
prop.table(table(NoU$from.MN))
standard deviation of the sample proportion of students who are from Minnesota.
=sqrt(p^(1-p^)/n
=sqrt( 0.6079665(1- 0.6079665)/477)
=0.022
Solutionbii
shape of sampling proportion distribution =normal
as sample size n>30
shape of sampling proportion distribution is normal according to central limit theorem.