INES S STATISTICS nal examm C Queston 6 (of 12) 10.00 points Sähism, a religion

Question

INES S STATISTICS nal examm C Queston 6 (of 12) 10.00 points Sähism, a religion founded in the 15th century in India, ts going t through burmol due to a rapid decline in the who wear turbans (Washington Post, March 29, 2009) The tedious task of combing hair and a desire to assmate has led to apprormately25% of Skh youths up the number of Sikh youths who wear turbans (Washington Post, turban a, whatis the probabarythat exact ytwon a random sample ofthe sah youths wear a turban?Do not round intermediate calculations. Round your final answers to 4 decimal places,) b. What is the probablity that two or more in a random sample of tive Sikh youths wear a turbsn? (Do not round intermediate calculations. Round your final answers to 4 decimal places.) Probablity sample of five Sikh youths? (Do not round intermediate calculations. Round your final answers to e. What is the probabilty that more than the expected number of Skh youths wear a turbian in a random 4 decimal places.) d·What is the probabley that more than the expected number of Sich youths wear trtan n a random sample of 10 5ilkh youths? (Do not round intermediate calculations. Round your final answers to 4 decimal places.) eBook & Resources O Type here to search

Explanation / Answer

Solution;-

p(Giving Turban) = 0.25

P(Turban) = 0.75

a) The probabiity that exactly 2 out of 5 sikh youths are wearing turban is 0.0879.

x = 2

By applying binomial distribution:-

P(x, n) = nCxpx*(1-p)(n-x)

P(x = 2) = 0.0879

b) The probabiity that 2 or more out of 5 sikh youths are wearing turban is 0.9844.

x = 2

By applying binomial distribution:-

P(x, n) = nCxpx*(1-p)(n-x)

P(x > 2) = 0.9844

c) The probability that more than expected number of sikh youths wear a turban in a random sample of 5 is 0.6328.

E(x) = 3.75

By applying binomial distribution:-

P(x, n) = nCxpx*(1-p)(n-x)

P(x > 4) = 0.6328

d) The probability that more thaa expected number of sikh youths wear a turban in a random sample of 10 is 0.5256

E(x) = 7.5

By applying binomial distribution:-

P(x, n) = nCxpx*(1-p)(n-x)

P(x > 8) = 0.5256

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