Please find an answer for Q17 , Q18 For Q17, \'C:equal to\' is not the answer. P

Question

Please find an answer for Q17 , Q18

For Q17, 'C:equal to' is not the answer.

Part Ill: Applications I will be dealt 5 cards from a well shuffled standard deck of 52 playing cards. Problem 13 the sum of the chance that I get an Ace and the chance that I get a The probability of the event that I get an Ace or a King is (017) 2 King, because (Q18)? A less thari B: greater than D. none of the above A one evert lS subset of the other B the events are mutually exclusive C: the intersection of the events is not empty D. Ih events are dependent E: the events are independent F: none of the ebove C: equal to Answers

Explanation / Answer

Solution:

Q17 = equal to

Q18 = the events are mutually exclusive

total number of cards = 52

number of Aces = 4

number of kings = 4

Probability we get Ace or a king = ( 4 + 4 ) / 52 = 8/52 = 0.1538

sum of chance of getting an Ace and chance of getting a King = ( 4 / 52) + ( 4 / 52) = 0.0769 + 0.0769

= 0.1538

The probability of the event that i get an ace or a King is (Q17) Equal to the sum of the chance that i get

a an Ace and chance that i get a King becaus ( Q18) the events are mutually exclusive

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