This Question: 1 pt 1 of 11 This n a recent poi 802 duts were asked to identity
ID: 3051728 • Letter: T
Question
This Question: 1 pt 1 of 11 This n a recent poi 802 duts were asked to identity their tavoxite seat when they ty, and 486 of them chose a window seat Use a o.05 signiicance evlo st the caim that the majnity of d tr indow seals wh y ty ienialy he nul typo which oflheblowing the hypotesis test to be conducted H, p.05 H paos Hps H, p0S What is the les stasic? Round to o alpaces as needed) Whait is the conclusion aboul the nul hypotesis? &Raject; the nul hypothesis because the P.value is greater than the significance levela C. Fail w reject the null typothesis because the P.alue is less than or equal to the sincance level, s the tinal conclusion? Thene is not sufficent evidence to support the claim that the majorty of aduts prefer window seats when they y There in suficiet evidence to warrnt rejection of the claim thail the majotity of aduits preer window seats when they y D. There s nosucent evidence to wamant rejection of the claim that the maity of duts preerwwts when they y Type here to search Dil Prtsen Home UndExplanation / Answer
n= 802 ,X= 496
p= 496/802= 0.618
a) Null hypothesis H0: P= 0.5
Alternative Hypothesis HA:P >0.5
Q= 1-P= 1-0.5= 0.5
Z= p-P/sqrt(PQ/n)
Z= 0.618-0.5/sqrt(0.5*0.5/802)
Z= 0.118/sqrt(0.000312)
Z= 0.118/0.01766
Z=6.68
The P-Value is 0.00001 The result is significant at p < 0.05.
Reject the null hypothesis because the P value is less than or equal to the significance level alpha
There is sufficient evidence to support the claim that the majority of adults prefer window seat when they fly.