Information The following applies to Questions 1 to 5 In a random sample of 150
ID: 3053038 • Letter: I
Question
Information The following applies to Questions 1 to 5 In a random sample of 150 Manitoba high school students, it is found that 66 of them have enrolled in university. Question 1 (1 point) what is the margin of error for a 97% confidence interval for the true proportion of Manitoba high school students who enroll in university Report your answer rounded to 3 decimal places. Your Answer: Question 2 (1 point) An article in a national magazine claims that less than half of all high school students in Manitoba go to university after they graduate. What is the P-value of the appropriate test of significance? Your Answer: Question 3 (1 point In the previous question, at the 396 level of significance, the decision rule is to reject Ho if z: Type "less than" or "greater than" (without quotes) in the first field. Type a value in the second field with 2 decimal places. Question 4 (1 point If the test in Question 2 is conducted at the 1% level of significance, what would be the power of the test if the true proportion of Manitoba high school students who enrolled in university were actually 0.37 Keep 6 decimal places in intermediate calculations and give your answer to 4 decimal places Your Answer: Question 5(1 point) If it were decided that the null hypothesis for the test in Question 2 would be rejected if p s 0.4453, then what would be the significance level of the test? Report your answer as a decimal with 2 decimal places. (The answer is not simply the value of 0.03 from Question 3 or the value of 0.01 from Question 4 This is a different situation.)Explanation / Answer
1)For a 997% CI, z score is 2.17.
p = proportion of population = 66/150 = 0.44
n = Sample = 150
The confidence Interval is: Sample Stas +/- z* SE
=> p (+/-) z*sqrt(p(1-p)/n)
=> 0.44 (+/-) 2.17 *sqrt(0.44(1-0.44)/150)
=>0.44 (+/-) 0.0879
Ans: 0.352 to 0.528
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