Check My Work (2 remaining) A sample of 9 days over the past six months showed t

Question

Check My Work (2 remaining) A sample of 9 days over the past six months showed that a dentist treated the following numbers of patients: 22, 24, 20, 18, 14, 21, 24, 20, and 26. If the number of patients seen per day is normally distributed, would an analysis of these sample data reject the hypothesis that the variance in the number of patients seen per day is equal to 10? Use a 10 level of significance. a. State the null and alternative hypotheses Ho: 2 ( Select H a: 2( Select b. Calculate the value of the test statistic (to 2 decimals) c. The p-value is Select d. What is your conclusion? Select

Explanation / Answer

The statistical software output for this problem is:

One sample variance hypothesis test:
2 : Variance of variable
H0 : 2 = 10
HA : 2 10

Hypothesis test results:

Hence,

a) Hypotheses:

H0 : 2 = 10 [2 is euqal to 10]
HA : 2 10 [2 is not equal to 10]

b) Test statistic = 10.4

c) P - value = 0.4761 [Greater than 0.1]

d) Do not reject Ho. We do not have sufficient evidence to reject the claim that the variance is 10.

Variable Sample Var. DF Chi-Square Stat P-value Data 13 8 10.4 0.4761

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