Math 2000 Statisties Section 14-Spring 20118 Quiz: Quiz2 Triola 4.2-4.5, 5.2 Thi
ID: 3061060 • Letter: M
Question
Math 2000 Statisties Section 14-Spring 20118 Quiz: Quiz2 Triola 4.2-4.5, 5.2 This Question: 1 pt Nykol Green & I 1218 10:17 PM Time Remaining: 01:41 09 Submilt Qu This Quiz: 20 pts possit 170t 20 (0 complete) Assume that a company hires employees on the differont business days of the month through (c) below (Assume 20 business days in a month) wth equal kelhood Completo parts (a) a. itf tewo different employees are randomly selected, what is the probalbility that they were both hired on the last business day of the month? The probabity is[] (Type meger or a smpiled baton) b. It twro diferent employees are randomly selecled, what is the probabilitythat they were both hired on the same ondened day of the business month? The prot atlity Type an integer or a simplified fraction) c. What is the probability that 5 people in the same department were all hired on the same The probabit.sL (Type an integer or a simplified fracton ) Is such an event unkely? ondered day of the business month? is such an event unlhely? O A. No because the probability that all 5 people were hired on the same ordered day of the business month is geaer han 005 a people sere hred on the same ordered day of the busness month is less than or equal to 0 05 D C Yes because the probabiythat all 5 people aere hined on the same ordered day of the business month is less than or equal to 0 t No, because the probability that all 5 O D. Yes, because ne probatiny that al S people we·twd on he sane odered day offe bane" moe-guer man OOS Clck to select your nswers F3 F4 FS F6 F7 F8 F9 F10 F11 F12 8Explanation / Answer
a)
An employee can be selected on any of the day from 20 BDs. Probability of selecting an employee on Last day of the month is 1/20.
As the selection of 2 employees is independent.
2 employees can be selected with a probability of 1/20 * 1/20 = 1/400
Required probability is 1/400
b)
Probability of selecting an employee on any particular day is 1/20. Two employees can be selected with probability of 1/400
However, there are 20 BDs and any one from 20 can be selected in 20C1 = 20 ways for the selection of two employees.
Hence required probability = 1/20 * 1/20 * 20 = 1/20
c)
If there are 5 such people to be selected
Required probability = (1/20^5)*20 = 1/160000 = 0.00000625
Is such an event unlikely - Option C