Student\'s name: Problem 3 (15 points) An m1 0.17 kg bird flying at a velocity o
ID: 306127 • Letter: S
Question
Student's name: Problem 3 (15 points) An m1 0.17 kg bird flying at a velocity of 6.3 m/s eastward sees ans westward. The unknown mass m2 heading straight toward it with a velocity of 33 m/s westw bird opens its mouth wide and enjoys a nice lunch. Right after the bird swa insect (and before the insect is digested) the velocity of the "bird-insect syst 4.0 m/s eastward. (All the velocities are measured relative to the grou the short time of the "collision" the air resistance, the bird and in to burning of calories and other effects alike are negligible.) a) What is the mass m2 of the insect? swallows the sect mass loss due To get full credit, please start with the appropriate conservation law and present all the steps of your solution. Present your answer with the precision of two significant figures.Explanation / Answer
3.
m1=0.17kg, v1i = 6.3m/s, m2=….? , v2i = -33.0m/s, vf = 4.0m/s
By law of conservation of momentum,
Pi = Pf
m1*v1i + m2*v2i = (m1+m2)*vf
Plugging values,
0.17*6.3 + m2*-33.0 = ( 0.17+ m2)*4.0
m2= 0.011 kg
m1=0.15kg, v1i = 7.1m/s, mB=….? , v2i = -45.0m/s, v1f= 3.0m/s, v2f= 27.0m/s
By law of conservation of momentum,
Pi = Pf
m1*v1i + m2*v2i = m1f*+m2* v2f
Plugging values,
0.15*7.1 + mB*-45.0 = 0.15*3.0+ mB*27.0
mB= 0.0085 kg