Ch 11 Sampling Distribution of a Sample Proportlon #Adapted Suppose a random sam

Question

Ch 11 Sampling Distribution of a Sample Proportlon #Adapted Suppose a random sample of 64 cyclists on the Fred Meijer Heartland Trail was taken, of which 48 were wearing helmets. (A) Find the 90% confidence intervals for the proportion of all cyclists on the Fred Meijer (B) Find the 95% confidence intervals for the proportion of all cyclists on the Fred Meijer (C) Find the 99% confidene intervals for the proportion of all cyclists on the Fred Meijer Heartland Trail who wore helmets. Heartland Trail who wore helmets. Heartland Trail who wore helmets.

Explanation / Answer

a)

90% CI =0.661 ; 0.839

b)

c)

                                                                                           x                    =   48 sample size n                    = 64 sample proportion     p x/n= 0.7500 std error       =Se            =(p*(1-p)/n) = 0.0541 for 90 % CI value of z= 1.6449 margin of error E=z*std error                            = 0.089 lower confidence bound=sample proportion-margin of error 0.661 Upper confidence bound=sample proportion+margin of error 0.839

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