Ancont broadcast of a television show had a 10 share, meaning that among 5000 mo
ID: 3069423 • Letter: A
Question
Ancont broadcast of a television show had a 10 share, meaning that among 5000 monitored households with TV sets in use, 10% of them were tuned to ths an Uso a 0.01 significance level to test the daim of an advertiser that among the households with TV sets n use, less than 15% woot nod into the p ogmidon fy the hypothesis, altomative hypothosis, tost statistic, P-valuo, condlusion about the null hypothesis, and final conclusion that addresses the original cdaim. Use the P-value mothod. Use the normal distribution as an approximation of the binomial distribution. Identify the null and altomative hypotheses. Choose the correct answer below A. Ho, p=0.85 Hy: p-0.85 O C. Hop 0.15 Mp p#0.15 O B. Ho: p 0.15 H: pExplanation / Answer
NULL HYPOTHESIS H0: p= 0.15
ALTERNATIVE HYPOTHESIS Ha: p< 0.15
P= 0.1 , alpha=0.01 and n= 5000
Under null hypothesis test statistic is
Z= P-p/sqrt(p*q/n)
Z= 0.1-0.15/sqrt(0.15*0.85/5000)
Z= -0.05/sqrt(0.1275/5000)
Z= -0.05/sqrt(0.0000255)
Z= -0.05/0.005
Z= -9.90
The P value is 0.0000
Reject H0. There is sufficient evidence to support the claim that 15% of the TV sets in use were tuned to the program.