Montgomery, Applied Statistics and Probability for Engineers, 7e RNTER VERSION .

Question

Montgomery, Applied Statistics and Probability for Engineers, 7e RNTER VERSION .BACKD.O NEXT 3.3.8 trees in a minimal growth condition at 350 parts per million (ppm), 12% at 430 pom slow growth), 49% at 40 ppm moderate growth and 35% at 630 ppm rapid growth what is the mean and standard deviation of the carbon dioxide atmosphere (in ppm) for these trees? The mean is The standard deviation is ppm. [Round your answer to one decimal place (e.g. 98.7).] ppm. [Round your answer to two decimal places (e.g. 98.76).] Click if you would like to Show Work for this question: Open Show Work By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor Question Attempts: 0 of 2 used SAVE FOR LATER Earn Maximum Points available only if you answer this question correctly in your first eNet

Explanation / Answer

Using R codes we can have the answers.

Code:

x <- c(0.04,0.12,0.49,0.35)
y <- c(350,430,540,630)
sum(x*y)
round(sqrt(sum(x*(y^2)) - sum(x*y)^2),2)

Output:

> x <- c(0.04,0.12,0.49,0.35)
> y <- c(350,430,540,630)
> sum(x*y)
[1] 550.7
> round(sqrt(sum(x*(y^2)) - sum(x*y)^2),2)
[1] 74.94

So, the mean is 550.7

and sd is 74.94

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