Measurements were recorded for the slapshot speed of 100 minor-league hockey pla
ID: 3072082 • Letter: M
Question
Measurements were recorded for the slapshot speed of 100 minor-league hockey players. These measurements were found to be normally distributed with mean of 87.481 mph and standard deviation of 4.2051 mph. Would it be unusual to record a value between 73.33 and 80.95 mph?
Part A options:
1)
2)
3)
4)
5)
Imagine that Exam 1 for Statistics 2160 this term will have 54 questions. Each question has 5 multiple choice options, giving you a probability of 0.2 of getting each question right purely by guessing. Assuming that you guess on all questions, what is the probability that you get less than 12 questions right on your exam?
Part B options:
1)
2)
3)
4)
5)
Imagine that Exam 1 for Statistics 2160 this term will have 66 questions. Each question has 5 multiple choice options, giving you a probability of 0.2 of getting each question right purely by guessing. Assuming that you guess on all questions, what is the probability that you get between 10 and 17 (inclusively) questions right on your exam?
Part C options:
1)
2)
3)
4)
5)
When rolling a die 108 times, what is the probability of rolling a 6 exactly 22 times?
Part D options:
1)
2)
3)
4)
5)
1)
A value in this interval is unusual.2)
A value in this interval is not unusual.3)
It is impossible for a value in this interval to occur with this distribution of data.4)
A value in this interval is borderline unusual.5)
We do not have enough information to determine if a value in this interval is unusual.Explanation / Answer
#1.
n = 100
mean = 87.481
sd = 4.2051
P(73.33 < X < 80.95)
= P((73.33 - 87.481)/(4.2051/sqrt(100)) < z < (80.95 - 87.481)/(4.2051/sqrt(100)))
= P(-33.6520 < z < -15.5311)
= 0
#2.
n = 54, n = 0.2
P(X < 12) = =BINOM.DIST(11,54,0.2,TRUE)
= 0.6064
#3.
P(10 <= X <= 17)
= P(X <= 17) - P(X <= 9)
= 0.9040 - 0.1249
= 0.7791
#4.
p = 1/6
P(X = 22) = 108C22 * (1/6)^22 * (5/6)^(108 - 22)
= 0.0573