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There are three hospitals in the Tulsa, Oklahoma, area. The following data show

ID: 3073060 • Letter: T

Question

There are three hospitals in the Tulsa, Oklahoma, area. The following data show the number of outpatient surgeries performed on Monday, Tuesday, Wednesday, Thursday, and Friday at each hospital last week. At the 0.01 significance level, can we conclude there is a difference in the mean number of surgeries performed by hospital or by day of the week?


1. Set up the null hypothesis and the alternate hypothesis.

2. State the decision rule for 0.01 significance level. (Round your answers to 2 decimal places.)

For Treatment: Reject H0 if F > ________

For blocks: Reject H0 if F > ________

3. Complete the ANOVA table. (Round your SS, MS and F to 2 decimal places.)

Number of Surgeries Performed Day St. Luke's St. Vincent Mercy Monday 30 45 34 Tuesday 12 16 12 Wednesday 31 28 23 Thursday 11 14 13 Friday 20 32 25


1. Set up the null hypothesis and the alternate hypothesis.

2. State the decision rule for 0.01 significance level. (Round your answers to 2 decimal places.)

For Treatment: Reject H0 if F > ________

For blocks: Reject H0 if F > ________

3. Complete the ANOVA table. (Round your SS, MS and F to 2 decimal places.)

Source SS df MS F Treatments Blocks Error Total

Explanation / Answer

Solution:

1. Set up the null hypothesis and the alternate hypothesis.

Answer:

Null hypothesis: H0: There is no any statistically significant difference in the mean number of surgeries performed by hospital or by day of the week.

Alternative hypothesis: Ha: There is a statistically significant difference in the mean number of surgeries performed by hospital or by day of the week.

2. State the decision rule for 0.01 significance level. (Round your answers to 2 decimal places.)

Answer:

For treatment, we are given = 0.01, df1 = 2, df2 = 8, so by using F-table or excel, F critical value = 8.649111

For Treatment: Reject H0 if F > 8.65

For blocks, we are given = 0.01, df1 = 4, df2 = 8, so by using F-table or excel, F critical value = 7.006077

For blocks: Reject H0 if F > 7.01

3. Complete the ANOVA table. (Round your SS, MS and F to 2 decimal places.)

Answer:

Required

Required ANOVA table by using Excel is given as below:

MS = SS/df

F for treatment= MST/MSE

F for block = MSB/MSE

Source

SS

df

MS

F

F-critical

P-value

Treatments

116.93

2

58.47

3.76

8.65

0.07

Blocks

1211.60

4

302.90

19.48

7.01

0.00

Error

124.40

8

15.55

Total

1452.93

14

Source

SS

df

MS

F

F-critical

P-value

Treatments

116.93

2

58.47

3.76

8.65

0.07

Blocks

1211.60

4

302.90

19.48

7.01

0.00

Error

124.40

8

15.55

Total

1452.93

14