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Assume there is a medical test to diagnose a disease. If a person has the diseas

ID: 3073680 • Letter: A

Question

Assume there is a medical test to diagnose a disease. If a person has the disease, the probability of having positive test result is 98 percent. If a person does not have the disease, the probability of having negative test results is 99.6 percent. The probability that a person has a disease is 1 percent in the population.

Answer the following questions:

a) If a person has a positive test result, what is the probability that he/she has the disease?

b) If a person has a positive test result, what is the probability that s/he doesn’t have the disease?

c) If a person has a negative test result, what is the probability that he/she doesn’t have the disease?

d) If a person has a negative test result, what is the probability that s/he has the disease?

Note: Use the following notation in your answer:

D: Person with disease

ND: Person without disease

+T: Positive test result

- T: Negative test result

Write each question in the form of mathematical notation for conditional probability.

Calculate the answer using two methods:

1. Bayes’ rule and conditional probability equations.

2. Draw a table, assume a population (e.g. 1 million) and provide numerical answers

Explanation / Answer

                                  Has the disease               Does not have the disease                  Total

Test positive             9800                                         3960                                       13760

Test negative                 200                                          986040                                    986240

Total                           10000    990000 1000000

a) P(has the disease | Test positive) = P(has the disease and test positive )/P(Test Positive)

= 9800/13760 = 0.7122

b) P(Doesn't have the disease | Test positive) =    P(Doesn't have the disease and test positive)/P(Test positive) = 3960/13760 = 0.2878

c) P(Doesn't have the disease | Test negative) =    P(Doesn't have the disease and test negative)/P(Test negative) = 986040/986240 = 0.9998

d) P(has the disease | Test negative) =    P(has the disease and test negative)/P(Test negative)

= 200/986240 = 0.0002