After today\'s lecture, we should have a rough idea about expectation for discre

Question

After today's lecture, we should have a rough idea about expectation for discrete random variables. Here is one challenge for you. Your "Probability Ice-Bucket/Push-Up Challenge": Question: Assume that ALS started the ICE BUCKET CHALLENGE and nominated 3 people to participate in the challenge. Each person has a probability P to complete the challenge (no need to donate) and nominate 3 others. Otherwise, he/she should donate 100 USD. Assume there are enough people to nominate and each person makes his/her decision independently. What is the expected (average) amount of donation ALS can get?

Explanation / Answer

E(Y) = 100 (1 - P) + P * 3E(Y)

E(Y) ( 1 - 3p) = 100 (1 - P)

or

E(Y) = 100(1 - p)/(1 - 3p)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---